Самара 2011 вариант 2 С2
№ задачи в базе 716
В правильной четырёхугольной призме ABCDA'B'C'D' точки O и O' - центры оснований призмы, точки P и K - середины рёбер AB и AD соответственно, точка M - середина отрезка [OO']. Найти угол между плоскостями (PKM) и (ABС), если , AA'=
Ответ:
Ключевые слова:
Задания ЕГЭ части 2 Задачи 14 на стереометрию Геометрия Стереометрия Угол между плоскостями Призма Задачники Пособия Самара 2011 Учебное пособие Тренировочные материалы для подготовки к ЕГЭ
ФИПИ 2025 🔥
ФИПИ 2025 🔥
Примечание:
Самара 2011 вариант 2 С2
![В правильной четырёхугольной призме ABCDA'B'C'D' точки O и O' - центры оснований призмы, точки P и K - середины рёбер AB и AD соответственно, точка M - середина отрезка [OO']. Найти угол между плоскостями (PKM) и (ABС), если `AB=3sqrt2`, AA'=`3sqrt3` 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🔥 Оценки экспертов решений задания 14 на стереометрию ЕГЭ по математике профильного уровня. Сканы реальных работ прошлых лет
